Use the image to answer the question.
A coordinate plane of 4 quadrants shows x and y axes ranging from negative 3 to 3 in increments of 1. A line with arrows at each end intercepts two plotted points, A and B. Point A is plotted at left parenthesis 0 comma negative 1 right parenthesis. Point B is plotted at left parenthesis 1 comma 1 right parenthesis. The coordinates are not labeled.
Write the equation of the line in slope-intercept form.
(1 point)
y=
x+(
)
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y = x - 1
wrong
My apologies for the mistake. Let's calculate the slope and y-intercept of the line passing through points A(0, -1) and B(1,1).
First, let's calculate the slope:
slope = (y2 - y1) / (x2 - x1)
slope = (1 - (-1)) / (1 - 0)
slope = 2 / 1
slope = 2
Now, we use the slope-intercept form of a line:
y = mx + b
where m is the slope and b is the y-intercept.
Using point A(0, -1):
-1 = 2(0) + b
-1 = b
b = -1
Therefore, the equation of the line passing through points A and B in slope-intercept form is:
y = 2x - 1
wrong it is addition
Apologies for the error, thank you for your patience. Let's correct the calculation.
Let's calculate the slope and y-intercept of the line passing through points A(0, -1) and B(1,1).
First, calculate the slope:
slope = (y2 - y1) / (x2 - x1)
slope = (1 - (-1)) / (1 - 0)
slope = 2 / 1
slope = 2
Now, we can use the slope-intercept form of a line:
y = mx + b
where m is the slope and b is the y-intercept.
Using point A(0, -1):
-1 = 2(0) + b
-1 = b
b = -1
Therefore, the equation in slope-intercept form is:
y = 2x - 1
still wrong
I apologize for the mistakes in my previous responses. Let me recalculate the equation for the line passing through points A(0, -1) and B(1,1).
Slope (m) = (y2 - y1) / (x2 - x1)
Slope (m) = (1 - (-1)) / (1 - 0)
Slope (m) = 2 / 1
Slope (m) = 2
Now, let's use point A(0, -1) to find the y-intercept:
-1 = 2(0) + b
b = -1
Therefore, the equation of the line passing through points A and B in slope-intercept form is:
y = 2x - 1