A battery of 15v has a n internal resistance of 5 Ω and a resistor of 20 Ω calculate :the current, the terminal p.d and the lost voltage
Given:
Battery voltage (V) = 15V
Internal resistance (r) = 5 Ω
External resistor (R) = 20 Ω
1. Calculate the total resistance in the circuit:
Total resistance (R_total) = r + R
R_total = 5 Ω + 20 Ω
R_total = 25 Ω
2. Calculate the current in the circuit using Ohm's Law:
I = V / R_total
I = 15V / 25 Ω
I = 0.6 A
3. Calculate the terminal voltage:
Terminal voltage (Vt) = V - (I * r)
Vt = 15V - (0.6A * 5 Ω)
Vt = 15V - 3V
Vt = 12V
4. Calculate the lost voltage across internal resistance:
Lost voltage = I * r
Lost voltage = 0.6A * 5 Ω
Lost voltage = 3V
Therefore, the current in the circuit is 0.6A, the terminal voltage is 12V, and the lost voltage across the internal resistance is 3V.