According to one study, 61% of the population swallow at least one spider per year in their sleep.
Based on this study, what is the probability that exactly 7 of 10 randomly selected people have
swallowed at least one spider in their sleep in the last year.
(1 point)
70%
22%
1%
34%
This can be calculated using the binomial probability formula:
P(X=k) = nCk * p^k * (1-p)^(n-k)
where n = 10 (number of randomly selected people), k = 7, p = 0.61 (probability of swallowing at least one spider per year), and 1-p = 0.39
Plugging in the values:
P(X=7) = 10C7 * (0.61)^7 * (0.39)^3 = 120 * 0.061337 * 0.027729 = 0.2005
Therefore, the probability that exactly 7 of 10 randomly selected people have swallowed at least one spider in their sleep in the last year is 20.05%.
So the closest option to this answer would be 22%.