What would be the new volume of oxygen gas when pressure remains constant if the temperature changed from 33.5 oC to 52.3 oC and its initial volume was 845 mL?
To find the new volume of oxygen gas when the temperature changes from 33.5 oC to 52.3 oC, we can use the combined gas law equation:
V1/T1 = V2/T2
Where:
V1 = initial volume = 845 mL
T1 = initial temperature = 33.5 oC + 273.15 = 306.65 K
T2 = final temperature = 52.3 oC + 273.15 = 325.45 K
V2 = final volume (unknown)
Plugging in the values:
845 mL / 306.65 K = V2 / 325.45 K
Solving for V2:
V2 = (845 mL x 325.45 K) / 306.65 K
V2 = 897.35 mL
Therefore, the new volume of oxygen gas when the temperature changes from 33.5 oC to 52.3 oC while keeping the pressure constant would be approximately 897.35 mL.