Mr. Bergstrom has two water storage tanks near his vegetable garden. One morning, tank A contained 2 gallons more than 4 times the number of gallons of water in tank B. At that time, tank A had a total of 46 gallons of water.
Select the equation that represents the given situation and find the number of gallons of water in tank B.
A.
4x + 2 = 46; 11 gallons
B.
4x + 2 = 46; 21 gallons
C.
2x + 4 = 46; 11 gallons
D.
2x + 4 = 46; 21 gallons
C. 2x + 4 = 46; 11 gallons
Explanation: Let x represent the number of gallons of water in tank B. According to the problem, tank A contained 2 gallons more than 4 times the number of gallons in tank B. This can be represented as 4x + 2. Since the total number of gallons in tank A is given as 46, we can set up the equation 4x + 2 = 46.
Solve for x:
4x + 2 = 46
4x = 44
x = 11
Therefore, there are 11 gallons of water in tank B.