Identify the slope and y-intercept of the line. Provide the most simplified form of the slope

0,-3 -4,0

To find the slope, use the formula:

slope = (y2 - y1) / (x2 - x1)

where (x1, y1) = (0, -3) and (x2, y2) = (-4, 0).

slope = (0 - (-3)) / (-4 - 0)
slope = 3 / -4
slope = -3/4

The y-intercept is the y-coordinate where the line intersects the y-axis. To find the y-intercept, substitute one of the given points into the slope-intercept form of a line, y = mx + b, where m is the slope:

Using point (0, -3):

-3 = (-3/4)(0) + b
-3 = b

Therefore, the y-intercept is -3.

Slope: -3/4
Y-Intercept: -3

Identify the slope and the white incerpt of the line provide the most simplified form of the slope.

Table:x:0,9,18. Y 3,6,9

To find the slope between the points (0, 3) and (9, 6):

slope = (y2 - y1) / (x2 - x1)

where (x1, y1) = (0, 3) and (x2, y2) = (9, 6).

slope = (6 - 3) / (9 - 0)
slope = 3 / 9
slope = 1/3

Therefore, the slope in the most simplified form is 1/3.

To find the y-intercept, substitute one of the given points into the slope-intercept form of a line, y = mx + b, where m is the slope.

Using point (0, 3):

3 = (1/3)(0) + b
b = 3

Therefore, the y-intercept is 3.

Slope: 1/3
Y-Intercept: 3

Write the equation of the slope intercept form

1,1 0,-1

To find the equation of the line passing through the points (1, 1) and (0, -1), we first need to calculate the slope.

Let's calculate the slope using the formula:

slope = (y2 - y1) / (x2 - x1)

Given points are:
(x1, y1) = (1, 1)
(x2, y2) = (0, -1)

slope = (-1 - 1) / (0 - 1)
slope = -2 / -1
slope = 2

Now that we have found the slope, we can use the point-slope form formula to write the equation of the line in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept.

Using the point (1, 1):

y - y1 = m(x - x1)
y - 1 = 2(x - 1)
y - 1 = 2x - 2
y = 2x - 1

Therefore, the equation of the line passing through the points (1, 1) and (0, -1) in slope-intercept form is y = 2x - 1.

Y=2x +_?

To determine the y-intercept when the equation of the line is in the form y = 2x + b, we need to know the value of the y-intercept, which represents where the line crosses the y-axis.

The 2x indicates the slope of the line, and the 'b' term represents the y-intercept. Since the y-intercept is missing in the equation y = 2x + ?, we can't provide the exact value of the y-intercept.

If the y-intercept were provided, the equation would be in the form y = 2x + b, where 'b' is the y-intercept value. With the information given, we would need to know the value of 'b' to determine the full slope-intercept equation.

If you are looking for the general form of the equation y = 2x + b without the specific y-intercept, it would be y = 2x + b where b is any real number, as the value of the y-intercept would not be specified.

Wrong

I apologize for the confusion in the previous message. Let's correct it:

Given the equation y = 2x + b, we know that the coefficient of x is the slope and b is the y-intercept. However, since you are looking for the equation in the slope-intercept form y = mx + b with the slope 'm' and the intercept 'b', the correct equation should be:

y = 2x + b

The y-intercept 'b' for this equation is the unknown part, as it represents the constant term that affects only the y-value when x is 0. If the y-intercept value is not given, we cannot determine the specific value of 'b' in this case.
Please let me know if you need further clarification or if there is a specific value of 'b' you are looking for.

The line of the slope has points B 1,1 and A0,-1

Now write the correct equation for slope form