Use the image to answer the question.
An illustration of a scatterplot graph shows x-axis ranging from 0 to 10 in increments of 1 and y-axis ranging from 0 to 50 in increments of 10. Multiple points are plotted around a line that points downward to the right with an arrowhead on the bottom.
The line passes approximately through left parenthesis 0 comma 45 right parenthesis, left parenthesis 2 comma 25 right parenthesis, left parenthesis 3 comma 15 right parenthesis, and left parenthesis 4.5 comma 0 right parenthesis. 13 points are plotted close to the line.
Write an equation in slope-intercept form of the trend line.
(1 point)
y=
-10x+50
wrong
Apologies for the mistake.
The correct equation in slope-intercept form of the trend line is:
y = -10x + 50
THATS wrong
I apologize for the error. Let's calculate the slope and y-intercept of the trend line using two points on the line, for example, (0, 45) and (4.5, 0).
Slope (m) = (y₂ - y₁) / (x₂ - x₁)
Slope (m) = (0 - 45) / (4.5 - 0)
Slope (m) = -45 / 4.5
Slope (m) = -10
Now that we have the slope, we can use it to calculate the y-intercept (b) using the point (0, 45) and the slope.
y = mx + b
45 = -10(0) + b
b = 45
Therefore, the equation in slope-intercept form of the trend line is:
y = -10x + 45
Thank you for your patience, and I appreciate your understanding.