The areas of two similar octagons are 112 in." and 63 in.2. What is the ratio (larger to smaller) of their perimeters?
(1 point)
16
3
4
16 9
413
The ratio of the areas of two similar figures is equal to the square of the ratio of their corresponding side lengths.
Let the side lengths of the larger octagon be x and the side lengths of the smaller octagon be y.
Therefore, (x/y)^2 = 112/63
x/y = √(112/63) = √(16/9) = 4/3
The ratio of their perimeters (larger to smaller) would also be 4/3, so the answer is 4.