0.400 mol of octane is allowed to react with 0.800 mol of oxygen.
How many moles of water are produced in this reaction?
First, we need to write and balance the chemical equation for the reaction between octane and oxygen to produce water:
2 C8H18 (octane) + 25 O2 -> 16 CO2 + 18 H2O
Now, we can use the mole ratio from the balanced equation to calculate the moles of water produced:
0.400 mol of octane * (18 mol H2O / 2 mol C8H18) = 3.6 mol H2O
Therefore, 3.6 moles of water are produced in this reaction.