What is the theoretical yield of SO3 produced by 5.99 g of S?
First, we need to balance the chemical equation for the reaction in which sulfur reacts to form sulfur trioxide:
2S + 3O2 → 2SO3
Next, we need to calculate the molar mass of S and SO3:
S: 32.06 g/mol
SO3: 80.06 g/mol
Now we can determine the moles of S in 5.99 g:
moles S = mass / molar mass
moles S = 5.99 g / 32.06 g/mol = 0.187 mol S
Since the reaction ratio is 2 moles of S to 2 moles of SO3, we can determine the theoretical yield of SO3:
moles SO3 = (2 mol SO3 / 2 mol S) * 0.187 mol S
moles SO3 = 0.187 mol SO3
Finally, we can calculate the theoretical yield of SO3 in grams:
mass SO3 = moles SO3 * molar mass SO3
mass SO3 = 0.187 mol * 80.06 g/mol = 14.98 g
Therefore, the theoretical yield of SO3 produced by 5.99 g of S is 14.98 grams.