what is the theoretical yield of SO3 produced by 5.99g of S
To calculate the theoretical yield of SO3 produced by 5.99g of S, you need to first determine the molar mass of S and SO3.
1. Calculate the molar mass of S:
S = 32.06 g/mol
2. Calculate the molar mass of SO3:
S = 32.06 g/mol
O = 16.00 g/mol (3 atoms)
SO3 = 32.06 g/mol + (16.00 g/mol * 3) = 80.06 g/mol
3. Determine the moles of S in 5.99g:
moles of S = mass / molar mass
moles of S = 5.99g / 32.06 g/mol = 0.187 mol
4. Using the balanced chemical equation, determine the molar ratio between S and SO3:
2S + 3O2 -> 2SO3
From the equation, the ratio of S to SO3 is 1:2.
5. Calculate the moles of SO3 produced:
moles of SO3 = moles of S * (2 moles of SO3 / 1 mole of S)
moles of SO3 = 0.187 mol * 2 = 0.374 mol
6. Calculate the theoretical yield of SO3 produced in grams:
theoretical yield = moles of SO3 * molar mass of SO3
theoretical yield = 0.374 mol * 80.06 g/mol = 29.96 g
Therefore, the theoretical yield of SO3 produced by 5.99g of S is 29.96 grams.