Two long, parallel wires separated by 90 each carry currents of 2.0 in a horizontal direction.
Is there a question here? If you are dealing with magnetic forces, the directions of the currents is important.
To find the magnetic force between two parallel wires, you can use the formula:
F = (μ₀ * I₁ * I₂ * L) / (2π * d)
where:
- F is the magnetic force between the wires,
- μ₀ is the permeability of free space (μ₀ ≈ 4π × 10^(-7) T·m/A),
- I₁ and I₂ are the currents in each wire,
- L is the length of the wires, and
- d is the distance between the wires.
In this case, the given values are:
- I₁ = I₂ = 2.0 A (currents in both wires),
- L = 90 m (length of the wires), and
- d = 90 m (distance between the wires).
Plugging the values into the formula, we get:
F = (4π × 10^(-7) T·m/A) * (2.0 A) * (2.0 A) * (90 m) / (2π * 90 m)
Simplifying the expression, we find:
F = (4π × 10^(-7) T·m/A) * (2.0 A) * (2.0 A) * (1)
F = 4π × 10^(-7) N
Therefore, the magnetic force between the two wires is approximately 4π × 10^(-7) N.