What is the theoretical yield of SO produced by 3.15 g of S?
To calculate the theoretical yield of SO2 produced by 3.15 g of S, we need to first determine the molar mass of S and SO2.
The molar mass of S is 32.07 g/mol and the molar mass of SO2 is 64.07 g/mol.
Next, we need to calculate the number of moles of S present in 3.15 g:
Number of moles = mass / molar mass
Number of moles = 3.15 g / 32.07 g/mol
Number of moles = 0.0984 mol
Since the balanced chemical equation for the formation of SO2 from S is:
S + O2 -> SO2
we know that 1 mol of S will produce 1 mol of SO2. Therefore, the number of moles of SO2 produced will also be 0.0984 mol.
Finally, we can calculate the mass of SO2 produced:
Mass = number of moles x molar mass
Mass = 0.0984 mol x 64.07 g/mol
Mass = 6.30 g
Therefore, the theoretical yield of SO2 produced by 3.15 g of S is 6.30 g.