what mass of carbon dioxide is produced from the complete combustion of 6.20x10-3g of methane
To solve this problem, we first need to write the balanced chemical equation for the combustion of methane (CH4):
CH4 + 2O2 → CO2 + 2H2O
From the balanced equation, we can see that one mole of CH4 will produce one mole of CO2. The molar mass of CH4 is 16.05 g/mol, so 6.20x10-3g of CH4 is equal to 6.20x10-3/16.05 = 3.86x10-4 moles of CH4.
Therefore, the amount of CO2 produced from the complete combustion of 6.20x10-3g of methane is also 3.86x10-4 moles. The molar mass of CO2 is 44.01 g/mol, so the mass of CO2 produced is 3.86x10-4 x 44.01 = 0.0170 g.