How many molecules (not moles) of NH3 are produced from 2.99×10-4 g of H2?
To calculate the number of molecules produced, we first need to determine the number of moles of H2 present in 2.99×10^-4 g of H2.
The molar mass of H2 is 2 g/mol, so we can calculate the number of moles of H2 as follows:
Number of moles = mass / molar mass
Number of moles = 2.99×10^-4 g / 2 g/mol
Number of moles = 1.495×10^-4 mol
From the balanced chemical equation for the reaction, we know that 3 moles of H2 produce 2 moles of NH3. Therefore, we can calculate the number of moles of NH3 produced from 1.495×10^-4 mol of H2:
Number of moles of NH3 = (1.495×10^-4 mol / 3 mol) x 2 mol
Number of moles of NH3 = 9.97×10^-5 mol
Finally, we can calculate the number of molecules of NH3 produced from 9.97×10^-5 mol NH3:
Number of molecules = number of moles x Avogadro's number
Number of molecules = 9.97×10^-5 mol x 6.022×10^23 molecules/mol
Number of molecules = 6.0082×10^19 molecules
Therefore, 6.0082×10^19 molecules of NH3 are produced from 2.99×10^-4 g of H2.