How many grams of NH3 can be produced from 2.42 mol of N2 and excess H2.
First, we need to write the balanced chemical equation for the reaction:
N2 + 3H2 -> 2NH3
From the equation, we can see that 1 mol of N2 produces 2 mol of NH3. Therefore, 2.42 mol of N2 would produce:
2.42 mol N2 x (2 mol NH3 / 1 mol N2) = 4.84 mol NH3
Now, we need to convert the moles of NH3 to grams. The molar mass of NH3 is 17.03 g/mol.
4.84 mol NH3 x 17.03 g/mol = 82.3 g NH3
Therefore, 82.3 grams of NH3 can be produced from 2.42 mol of N2 and excess H2.