How many grams of NH can be produced from 2.42 mol of Ne and excess H2.
First, we need to write the balanced chemical equation for the reaction between Ne and H2 to produce NH3.
2 Ne + 3 H2 -> 2 NH3
From the balanced chemical equation, we can see that 2 moles of NH3 are produced for every 2 moles of Ne used.
So, we can calculate the moles of NH3 produced from 2.42 mol of Ne by using the ratio from the balanced chemical equation:
2.42 mol Ne x (2 mol NH3 / 2 mol Ne) = 2.42 mol NH3
Now, we need to convert the moles of NH3 to grams. The molar mass of NH3 is 17.031 g/mol.
2.42 mol NH3 x 17.031 g/mol = 41.22 g NH3
Therefore, 41.22 grams of NH3 can be produced from 2.42 mol of Ne and excess H2.