two containers designed to hold water or side-by-side both in the shape of a cylinder container a has a diameter of 32 feet and a height of 16 feet container be has a diameter of 30 feet and a height of 18 feet container a is full of water and the water is pumped into container be until container be is full after pumping is complete. What is the volume of the water remaining container a to the nearest 10th of the nearest cubic foot
To find the volume of water remaining in container A after pumping all the water into container B, we first need to calculate the volume of water in both containers.
Volume of container A:
radius = diameter/2 = 32ft/2 = 16ft
height = 16ft
Volume = πr^2h = π(16ft)^2(16ft) = 4096π ft^3
Volume of container B:
radius = 30ft/2 = 15ft
height = 18ft
Volume = πr^2h = π(15ft)^2(18ft) = 4050π ft^3
After pumping all the water from container A into container B, the remaining water volume in container A is:
Remaining volume = Volume of container A - Volume of container B
Remaining volume = 4096π ft^3 - 4050π ft^3
Remaining volume ≈ 46π ft^3
Remaining volume ≈145 cubic feet (rounded to the nearest cubic foot)
Therefore, the volume of water remaining in container A after pumping all the water into container B is approximately 145 cubic feet.