Solve the system of equations
Negative 4X plus 6Y equals 38
X minus 5Y equals -20
To solve this system of equations, we can use the method of substitution or elimination.
First, let's solve the second equation for X:
X = 5Y - 20
Now, substitute X = 5Y - 20 into the first equation:
-4(5Y - 20) + 6Y = 38
-20Y + 80 + 6Y = 38
-14Y + 80 = 38
-14Y = -42
Y = 3
Now, substitute Y = 3 back into X = 5Y - 20:
X = 5(3) - 20
X = 15 - 20
X = -5
Therefore, the solution to the system of equations is X = -5 and Y = 3.