Find the distance between these two points using the Pythagorean Theorem. Which choice is correct? (1 point) Responses 52+72=136−−−√ 5 squared plus 7 squared is equal to square root of 136 32−−√−52=20−−√ square root of 3 squared end root minus 5 squared is equal to square root of 20 (62+102)−−−−−−−−−√=136−−−√ square root of open paren 6 squared plus 10 squared close paren end root is equal to square root of 136 62−−√+32=25−−√ square root of 6 squared end root plus 3 squared is equal to square root of 25

Question

Find the distance between these two points using the Pythagorean Theorem. Which choice is correct? (1 point) Responses 52+72=136−−−√ 5 squared plus 7 squared is equal to square root of 136 32−−√−52=20−−√ square root of 3 squared end root minus 5 squared is equal to square root of 20 (62+102)−−−−−−−−−√=136−−−√ square root of open paren 6 squared plus 10 squared close paren end root is equal to square root of 136 62−−√+32=25−−√ square root of 6 squared end root plus 3 squared is equal to square root of 25

Answer 1

The correct answer is:

(62+102)−√=136√

This is because the formula for finding the distance between two points using the Pythagorean Theorem is √(Δx^2 + Δy^2), where Δx is the difference in x-coordinates and Δy is the difference in y-coordinates. In this case, (6-3)^2 + (10-5)^2 = √(3^2 + 5^2) = √(9 + 25) = √34.

Therefore, the correct choice is the third one: (62+102)−√=136√.