Cos(theta)sin(theta)-2cos(theta)=0
To solve this equation, we can first factor out a common factor of cos(theta):
cos(theta)(sin(theta) - 2) = 0
Now we can set each factor equal to zero:
cos(theta) = 0
sin(theta) - 2 = 0
For the first equation, cos(theta) = 0 when theta = π/2 or 3π/2.
For the second equation, sin(theta) - 2 = 0 when sin(theta) = 2, which has no real solutions.
Therefore, the solutions to the equation cos(theta)sin(theta) - 2cos(theta) = 0 are theta = π/2 and theta = 3π/2.