The length of a rectangle is 5 longer than its width.If the perimeter of the rectangle is 38yr, find its area.
Let the width of the rectangle be x.
Then the length of the rectangle will be x + 5.
The perimeter of a rectangle is given by the formula: P = 2l + 2w, where P is the perimeter, l is the length, and w is the width.
Given that the perimeter of the rectangle is 38, we have:
38 = 2(x + 5) + 2x.
Simplifying the equation, we get:
38 = 2x + 10 + 2x,
38 = 4x + 10,
4x = 28,
x = 7.
So the width of the rectangle is 7 and the length is 7 + 5 = 12.
The area of the rectangle is given by the formula: A = length x width.
Therefore, the area of the rectangle is:
A = 12 x 7 = 84 square units.