1. Review the graphs of a system of two linear equations in two variables: x − 5y = 7 and 3x − 2y = −4. Find the solution to both equations. Note the answer isn't (3, 2) or (3, -2) or a fraction.
The intersection point is (____), (____).
THAT IS WRONG
(3, -2)
1. Review the graphs of a system of two linear equations in two variables: x − 5y = 7 and 3x − 2y = −4. Find the solution to both equations. Note the answer isn't (3, 2) or (3, -2) or a fraction.
On a graph there's 3x - 2y = -4 and x - 5y = 3.
The intersection point is (____), (____).
I'm telling you all the information please tell me the correct answer.
I apologize for the mistake in my previous responses. Let's reevaluate the system of equations x - 5y = 7 and 3x - 2y = -4.
To find the solution, we can solve these equations simultaneously by either substitution or elimination. Let's use the elimination method.
Given:
x - 5y = 7 (Equation 1)
3x - 2y = -4 (Equation 2)
Multiplying Equation 1 by 3, we get:
3x - 15y = 21
Subtracting Equation 2 from the modified Equation 1:
(3x - 15y) - (3x - 2y) = 21 - (-4)
-13y = 25
y = -25/13
Now, substitute y = -25/13 into Equation 1:
x - 5(-25/13) = 7
x + 125/13 = 7
x = 7 - 125/13
x = 91/13 - 125/13
x = -34/13
Therefore, the solution to the system of equations x - 5y = 7 and 3x - 2y = -4 is (-34/13, -25/13).
THE ANSWER IS NOT A FRACTION AND THE ANSWER IS NOT (3, 2) or (3, -2)
Given the system of equations:
1. x - 5y = 7
2. 3x - 2y = -4
Let's solve this system of equations:
From equation 1, we can express x in terms of y:
x = 7 + 5y
Now, substitute x in terms of y into equation 2:
3(7 + 5y) - 2y = -4
21 + 15y - 2y = -4
13y = -25
y = -25/13
Now, substitute y = -25/13 back into x = 7 + 5y:
x = 7 + 5(-25/13)
x = 7 - 125/13
x = (91 - 125)/13
x = -34/13
Therefore, the solution to the system of equations is x = -34/13 and y = -25/13. The correct point of intersection is (-34/13, -25/13).