A chemist prepares a solution of mercury (I) chloride Hg, CL) by measuring out 0.44 mg of mercury(I) chloride into a 150. mL volumetric flask and filling the flask to the mark with water.
Calculate the concentration in mol/L of the chemist's mercuryI) chloride solution. Be sure your answer has the correct number of significant digits.
To calculate the concentration of the mercury(I) chloride solution, we first need to convert the mass of the compound into moles.
The molar mass of mercury(I) chloride (HgCl) is 271.5 g/mol.
0.44 mg is equal to 0.00044 g.
Now, we can calculate the number of moles of mercury(I) chloride:
moles = mass / molar mass
moles = 0.00044 g / 271.5 g/mol
moles = 1.62 x 10^-6 mol
Next, we need to calculate the volume of the solution in liters:
150 mL = 0.150 L
Finally, we can calculate the concentration of the solution:
concentration = moles / volume
concentration = 1.62 x 10^-6 mol / 0.150 L
concentration ≈ 1.08 x 10^-5 mol/L
Therefore, the concentration of the chemist's mercury(I) chloride solution is approximately 1.08 x 10^-5 mol/L.