A chemist prepares a solution of magnesium fluoride MgF, by measuring out 1.18 mg of magnesium fluoride into a 350. ml volumetric flask and filling the ask to the mark with water.
alculate the concentration in mol/L of the chemist's magnesium fluoride solution. Be sure your answer has the correct number of significant digits.
To calculate the concentration of the magnesium fluoride solution, we need to first convert the mass of MgF2 to moles using the molar mass of MgF2.
The molar mass of MgF2 is 78.71 g/mol.
1.18 mg = 0.00118 g
Now we can calculate the moles of MgF2:
moles = mass / molar mass
moles = 0.00118 g / 78.71 g/mol
moles = 1.50 x 10^-5 mol
Now we can calculate the concentration of the solution:
concentration (mol/L) = moles / volume (L)
concentration = 1.50 x 10^-5 mol / 0.350 L
concentration = 4.29 x 10^-5 mol/L
Therefore, the concentration of the magnesium fluoride solution is 4.29 x 10^-5 mol/L.