Calculate the volume in liters of a 0.00228 mM calcium sulfate solution that contains 425. mmol of calcium sulfate (CaSO,). Be sure your answer has the correct number of significant digits.
1. First, we need to calculate the number of moles of CaSO4 in the solution:
Number of moles = 425 mmol = 0.425 mol
2. Next, we need to calculate the volume of the solution using the molarity formula:
Molarity = moles of solute / volume of solution (in liters)
0.00228 mM = 0.00000228 mol/L
Volume of solution = moles of solute / molarity
Volume = 0.425 mol / 0.00000228 mol/L
Volume = 186,403.51 L
3. Finally, we convert the volume from liters to mL (1 L = 1000 mL):
Volume = 186,403.51 L x 1000 mL/L
Volume = 186,403,510 mL
Therefore, the volume of the 0.00228 mM calcium sulfate solution that contains 425. mmol of CaSO4 is 186,403,510 mL or 1.86 x 10^8 mL with the correct number of significant digits.