Suppose 309. mL of DMSO and 474. mL of water are mixed, and the final solution has a volume of 744. mL. Note that the density of DMSO is 1.1 g/ Calculate the volume percent of DMSO in this solution.
Be sure your answer has the right number of significant digits.
To calculate the volume percent of DMSO in the solution, we first need to find the mass of each component present in the solution.
Volume of DMSO = 309 mL
Volume of water = 474 mL
Total volume of solution = 744 mL
Density of DMSO = 1.1 g/mL
Mass of DMSO = volume x density = 309 mL x 1.1 g/mL = 339.9 g
Mass of water = 474 mL x 1 g/mL = 474 g
Total mass of solution = 339.9 g + 474 g = 813.9 g
Now, we can calculate the volume percent of DMSO in the solution:
Volume percent = (volume of DMSO / total volume) x 100
Volume percent = (309 mL / 744 mL) x 100 = 41.53%
Therefore, the volume percent of DMSO in the solution is 41.5%.