Calculate the value of H3O | from the given [OH"] in each solution and label the solution as acidic, basic, or neutral. Be sure each of your answer entries
has the correct number of significant figures.
Note: The ion product of water = 1.0 x 10-14
Part 1 of 2
[OH-]=9.0x10-8M
[H30+]=
This solution is (Choose one)
Part 2 of 2
[OH-]=2.9 x 10^-4 M
H30+=
This solution is
(Choose one)
Part 1 of 2:
[H3O+] = (1.0x10^-14)/[OH-] = (1.0x10^-14)/(9.0x10^-8) = 1.1x10^-7 M
This solution is acidic.
Part 2 of 2:
[H3O+] = (1.0x10^-14)/[OH-] = (1.0x10^-14)/(2.9x10^-4) = 3.4x10^-11 M
This solution is basic.