can you help me with this Calculate the value of [OH" ] from the given | H3O+ | in each solution and label the solution as acidic, basic, or neutral. Be sure each of your answer entries has
the correct number of significant figures.
Note: Reference the Fundamental constants table for additional information.
Part 1 of 2
H30+=2.6x10-12 M
[OH-]=
This solution is
Part 2 of 2
H30+=9.8x1071
OH=
This solution is
M
(Choose one)
Part 1:
Using the equation Kw = [H3O+][OH-], we can plug in the given [H3O+] = 2.6x10^-12 M and solve for [OH-]:
Kw = (2.6x10^-12) x [OH-]
1.0x10^-14 = 2.6x10^-12 x [OH-]
[OH-] = 3.8x10^-3 M (rounded to 2 significant figures)
Therefore, the [OH-] in this solution is 3.8x10^-3 M and since [OH-] > 1.0x10^-7 M, it is a basic solution.
Part 2:
Using the equation Kw = [H3O+][OH-], we can plug in the given [H3O+] = 9.8x10^-7 M and solve for [OH-]:
Kw = (9.8x10^-7) x [OH-]
1.0x10^-14 = 9.8x10^-7 x [OH-]
[OH-] = 1.0x10^-8 M (rounded to 1 significant figure)
Therefore, the [OH-] in this solution is 1.0x10^-8 M and since [OH-] < 1.0x10^-7 M, it is an acidic solution.