Consider a binomial random variable X. If the probability the first success of this event occurs on the second trial is 0.25 what's the probability p this event will succeed on each trial?
A. 1/4
B. 1/8
C. .125
D. 1/2
E. 1
The probability p that the event will succeed on each trial can be calculated as follows:
P(X=1) = p(1-p)^1 = p(1-p) = 0.25
p - p^2 = 0.25
p - 0.25 = p^2
0.25 = 0.25^2
0.25 = 0.0625
Therefore, the probability p that the event will succeed on each trial is 0.25 or 1/4.
A. 1/4