A sample of iron weighing 111.6 g was subjected to heating, experiencing a temperature increase from 0°C to 20°C. The sample absorbed a total of 1004 J of energy during this process. What is the specific heat capacity of iron?
To calculate the specific heat capacity of iron, we can use the formula:
Q = mcΔT
Where:
Q = heat absorbed (1004 J)
m = mass of the sample (111.6 g = 0.1116 kg)
c = specific heat capacity of iron (unknown)
ΔT = change in temperature (20°C - 0°C = 20°C)
Plugging in the values:
1004 J = 0.1116 kg * c * 20°C
Solving for c:
c = 1004 J / (0.1116 kg * 20°C)
c = 451.08 J/(kg * °C)
Therefore, the specific heat capacity of iron is 451.08 J/(kg * °C).