The length of a rectangle is longer than its width.
If the perimeter of the rectangle is , find its area.
Let the width of the rectangle be x.
Therefore, the length of the rectangle is x + 1.
The perimeter of a rectangle is given by P = 2(l + w), where l is the length and w is the width.
So, the perimeter, P = 2(x + 1 + x) = 2(2x + 1) = 4x + 2
Given that the perimeter is P, we have P = 4x + 2.
Since the perimeter is given and we know the width (x), we can solve for x:
P = 4x + 2
26 = 4x + 2
4x = 24
x = 6
Therefore, the width of the rectangle is 6 units and the length is 7 units.
The area of a rectangle is given by A = l x w = (x + 1) x 6 = 6 x 7 = 42 square units.
Therefore, the area of the rectangle is 42 square units.