If w = 8 inches, x = 5 inches, y = 20 inches, and z = 11.3 inches, what is the total surface area of the exterior faces of the figure?
A.
960 square inches
B.
1,060 square inches
C.
760 square inches
D.
860 square inches
To find the total surface area of the exterior faces of the figure, we need to add up the surface areas of each face.
Given:
w = 8 inches
x = 5 inches
y = 20 inches
z = 11.3 inches
The figure consists of 6 faces: two faces with dimensions y by z, two faces with dimensions x by z, and two faces with dimensions x by y.
The surface area of a rectangle is calculated as length times width.
Therefore, the total surface area of the exterior faces of the figure is:
2(y * z) + 2(x * z) + 2(x * y) = 2(20 * 11.3) + 2(5 * 11.3) + 2(5 * 20)
= 2(226) + 2(56.5) + 2(100)
= 452 + 113 + 200
= 765
Therefore, the total surface area of the exterior faces of the figure is 765 square inches.
The closest option is:
C. 760 square inches