If there is a 62% chance of your favorite team winning the game then what is the percent chance that they do not win the game?
38% chance that they do not win the game.
This is calculated by subtracting the percentage chance of winning from 100%. So, 100% - 62% = 38%.
There is a jar that contains 9 marbles and 3 of them are blue. If you were to randomly draw 2 marbles (with replacement) what is the probability that both the marbles are not blue? Write your answer as a fraction. You do not need to simplify your faction.
First, let's calculate the probability of drawing a non-blue marble from the jar.
There are 6 non-blue marbles in the jar out of a total of 9, so the probability of drawing a non-blue marble on the first draw is 6/9.
Since we are replacing the marble after each draw, the probability of drawing a non-blue marble on the second draw is also 6/9.
To calculate the probability of both marbles being non-blue, we multiply the probabilities of the individual draws:
(6/9) * (6/9)
= 36/81
Therefore, the probability that both marbles drawn are not blue is 36/81.
The tree diagram below shows the distribution of cars sold and whether each type got upgrades or not. Click Here for Help Video
Find the probability of a random vehicle getting an upgrade.