Use the graph to answer the following questions.
You are helping to plan a community garden. Sprinklers need to be set up at each end of the garden plot for irrigation, plus one more at the midpoint.
A coordinate graph is shown. A line segment extends from point J, which is labeled 1 comma 5, down and to the right to point K, which is labeled 5 comma 0.
Question
Which equation correctly solves for distance in this situation?
(1 point)
Responses
d equals start root left parenthesis 5 minus 1 right parenthesis squared plus left parenthesis 0 minus 5 right parenthesis squared end root line break equals start root left parenthesis 4 right parenthesis squared plus left parenthesis negative 5 right parenthesis squared end root
Image with alt text: d equals start root left parenthesis 5 minus 1 right parenthesis squared plus left parenthesis 0 minus 5 right parenthesis squared end root line break equals start root left parenthesis 4 right parenthesis squared plus left parenthesis negative 5 right parenthesis squared end root
d equals start root left parenthesis 0 minus 5 right parenthesis squared times left parenthesis 5 minus 1 right parenthesis squared line break equals start root left parenthesis negative 5 right parenthesis squared times left parenthesis 4 right parenthesis squared
Image with alt text: d equals start root left parenthesis 0 minus 5 right parenthesis squared times left parenthesis 5 minus 1 right parenthesis squared line break equals start root left parenthesis negative 5 right parenthesis squared times left parenthesis 4 right parenthesis squared
d equals start root left parenthesis 0 minus 5 right parenthesis squared minus left parenthesis 5 minus 1 right parenthesis squared end root line break equals start root left parenthesis negative 5 right parenthesis squared minus left parenthesis 4 right parenthesis squared end root
Image with alt text: d equals start root left parenthesis 0 minus 5 right parenthesis squared minus left parenthesis 5 minus 1 right parenthesis squared end root line break equals start root left parenthesis negative 5 right parenthesis squared minus left parenthesis 4 right parenthesis squared end root
d equals start root left parenthesis 5 minus 1 right parenthesis plus left parenthesis 0 minus 5 right parenthesis end root line break equals start root left parenthesis 4 right parenthesis plus left parenthesis negative 5 right parenthesis end root
The correct equation to solve for distance in this situation is:
d = √[(5 - 1)^2 + (0 - 5)^2]
= √[4^2 + (-5)^2]
= √[16 + 25]
= √41
Therefore, the correct equation is: d = √41