For a short part of its trajectory (Δx=1,074 m
), the shuttlecock moves in an approximately straight line over a period of Δt=0,02 s
. The shuttlecock has a mass of m=5 g
.
Ignore the effects of air resistance. Also ignore the effects of gravity on the shuttlecock during this short part of its trajectory.
1.Calculate the magnitude of the average velocity (vavg
) of the shuttlecock over this period of its trajectory.
2. Calculate the magnitude of the average momentum (pavg
) of the shuttlecock over this period of its trajectory.
1. To calculate the magnitude of the average velocity (vavg), we use the formula:
vavg = Δx / Δt
Plugging in the values we have:
vavg = 1,074 m / 0.02 s
vavg = 53,700 m/s
Therefore, the magnitude of the average velocity of the shuttlecock over this period of its trajectory is 53,700 m/s.
2. To calculate the magnitude of the average momentum (pavg) of the shuttlecock, we use the formula:
pavg = m * vavg
Plugging in the values we have:
pavg = 0.005 kg * 53,700 m/s
pavg = 268.5 kg*m/s
Therefore, the magnitude of the average momentum of the shuttlecock over this period of its trajectory is 268.5 kg*m/s.