what is the average or mean slope of the function f(x)=(10(x^1/2)+4 on the interval [2,6]
A good approximation would be
[f(6) - f(2)]/4
which is the slope of the line joining the endpoints.
That would be 2.588
[f(6) - f(2)]/4
which is the slope of the line joining the endpoints.
That would be 2.588