Four friends A,B,C,D have same money among them one day they decided to equate the money, so first A gave B what B had initially, then B gave 'C" what c had initially. Again C gave D what D had initially and finally D has doubled the money of A. Thus each of them had equal sum of Rs. 48
49. What was the initial amount of B?
(A) Rs. 36
(B) Rs. 54 (C) Rs. 45
(D) Rs. 42
50. What was the amount with C after second transaction?
(ARs. 84
(B) Rs. 69
(C) Rs. 72
(D) Rs. 45
MATHS
What was the initial amount of A?
(A) 69
(B) 45
(C) 42
(D) 36
Let the initial amounts of A, B, C, and D be A, B, C, and D respectively.
After the first transaction, the amounts become:
A = A - B
B = 2B
C = C
D = D
After the second transaction, the amounts become:
A = A - B
B = 0
C = C + B = C
D = D
After the third transaction:
A = A - B
B = 0
C = C + B = C + B
D = D + C = D + C
After the fourth transaction:
A = A - B - 2D
B = 0
C = C + B = C + B = C
D = D + C = 2D
Given that each of them had equal amount of Rs. 48 at the end.
So, A = B = C = D = 48
Plugging this back into the transactions:
Initial amount of D = 48
So, D = 48
C = D = 48
B = C = 48
A = B + 48 = 96
So, the initial amount of A was Rs. 96, which is not in the options provided.
Therefore, the initial amount of A is not provided in the options given.