Four friends A,B,C,D have same money among them one day they decided to equate the money, so first A gave B what B had initially, then B gave 'C" what c had initially. Again C gave D what D had initially and finally D has doubled the money of A. Thus each of them had equal sum of Rs. 48
51. What was the initial amount of A?
(A) 69
(B) 45
(C) 42
(D) 36
Let the initial amount of each friend be x.
After the given transactions:
A = x - x = 0
B = 2x
C = 3x
D = 6x
According to the given conditions:
A + B + C + D = 4 * 48
0 + 2x + 3x + 6x = 192
11x = 192
x = 17.45
Therefore, the initial amount of A was:
A = x = 17.45
So, none of the options provided match the correct answer.