Stephanie wants to paint the door to her shed purple. How much paint will cover the door if it is 60 3/8 inches high, 36 3/5 inches long, and 2.2 inches wide? Round the answer to the nearest tenth.(1 point) Responses 4,827 square inches 4,827 square inches 4,665.7 square inches 4,665.7 square inches 4,826 3/4 square inches 4,826 Start Fraction 3 over 4 End Fraction square inches 4,846.1 square inches
To find the surface area of the door, we need to calculate the area of each of the four sides.
1. For the front side (60 3/8 inches high and 36 3/5 inches long):
Area = Height x Length
Area = (60 3/8) x (36 3/5)
Area ≈ 60.375 x 36.6
Area ≈ 2207.35 square inches
2. For the back side (60 3/8 inches high and 36 3/5 inches long) - same as front side:
Area ≈ 2207.35 square inches
3. For the two side panels (60 3/8 inches high and 2.2 inches wide):
Area = Height x Width
Area = 60.375 x 2.2
Area ≈ 132.825 square inches
Since there are two side panels, the total area for the side panels is 2 x 132.825 = 265.65 square inches
Now, to find the total surface area of the door, we sum up the areas of each side:
Total area = 2207.35 + 2207.35 + 265.65
Total area ≈ 4680.35 square inches
Rounded to the nearest tenth, the total paint needed to cover the door is approximately 4,665.7 square inches.
Therefore, the answer is:
4,665.7 square inches