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What is the expected freezing point of a 3.50 m aqueous solution of BaCl2 (Kfp=1.86C/m)? What is the boiling point (Kbp=0.512C/m? & which is affected to the greater extent, the boiling point or the freezing point?

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Dan

  1. Just look at the constants, freezing point depression is bigger.

    FP=orig - 1.86*3.50*3
    the three comes from the three ions per molecule.

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    bobpursley

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