X - y= -1
X-3y=-13
How could you check to see if the point (5, 6) is the solution to the Linear System of equations?
* Substitute 6 in for x and 5 in for y in one of the equations to see if the equation is true.
* Substitute 6 in for x and 5 in for y in both of the equations to see if both equations are true.
* Substitute 5 in for x and 6 in for y in one of the equations to see if the equation is true.
* Substitute 5 in for x and 6 in for y in both of the equations to see if both equations are true.
To check if the point (5, 6) is the solution to the given system of equations, we can substitute x=5 and y=6 into both equations:
1. x - y = -1
5 - 6 = -1
-1 = -1 (True)
2. x - 3y = -13
5 - 3(6) = -13
5 - 18 = -13
-13 = -13 (True)
Since both equations are true when x=5 and y=6, the point (5, 6) is indeed the solution to the linear system of equations.
Use one of the answers I gave you
Sure! Let's substitute x=5 and y=6 in the first equation x - y = -1:
5 - 6 = -1
-1 = -1
Since the equation is true, the point (5, 6) is the solution to the linear system of equations.
Substitute 6 in for x and 5 in for y in one of the equations to see if the equation is true.
* Substitute 6 in for x and 5 in for y in both of the equations to see if both equations are true.
* Substitute 5 in for x and 6 in for y in one of the equations to see if the equation is true.
* Substitute 5 in for x and 6 in for y in both of the equations to see if both equations are true.
Substitute 6 in for x and 5 in for y in one of the equations to see if the equation is true:
1. x - y = -1
6 - 5 = -1
1 = -1 (False)
Since the equation is false, the point (6, 5) is not the solution to the linear system of equations.