a certan population of mice, a single gene contiola fur color. There are ten possible alleles. 8, which leads to a black fur and W. which leads to while tur bdividuals with the geniotype BB will have a black le individuals with the genctype WW will have white fur, and individuals with the genotype BW will have gray Be Scientists recorded the tur color of 1,000 mice from the population. They found that 200 mice have black fur, 400 have gray lur and 400 have white ka Tori years later, the measurements are repeated Again, they recorded the fur color of 1,000 meas. They found that 400 have black tur 100 have gray he wnd 200 fave whale ha

Question

a certan population of mice, a single gene contiola fur color. There are ten possible alleles. 8, which leads to a black fur and W. which leads to while tur bdividuals with the geniotype BB will have a black le individuals with the genctype WW will have white fur, and individuals with the genotype BW will have gray Be Scientists recorded the tur color of 1,000 mice from the population. They found that 200 mice have black fur, 400 have gray lur and 400 have white ka Tori years later, the measurements are repeated Again, they recorded the fur color of 1,000 meas. They found that 400 have black tur 100 have gray he wnd 200 fave whale ha

Part A Show the Hardy Weinberg calculatione for the beginning and ending populations Include the values for the equation as well as the pandales. Show your work

Part B. Use the Hardy-Weinberg raksation to explten if this populationevolving or not. The propose a hypothesis about fewworment of the mice that would bead to these cosertiona

Answer 1

Part A:

Beginning population:
- Let p = frequency of allele for black fur (B)
- Let q = frequency of allele for white fur (W)

Given that there are 10 possible alleles, the total number of alleles in the population is 10*1000 = 10,000.

From the initial population data:
- 200 mice have black fur, so 2*200 = 400 alleles are for black fur.
- 400 mice have gray fur, so 2*400 = 800 alleles are for gray fur.
- 400 mice have white fur, so 2*400 = 800 alleles are for white fur.

Therefore, p = (400 + 800)/10000 = 0.12 and q = (800 + 800)/10000 = 0.16

Calculating genotype frequencies:
- BB (black fur): p^2 = 0.12^2 = 0.0144
- BW (gray fur): 2pq = 2*0.12*0.16 = 0.0384
- WW (white fur): q^2 = 0.16^2 = 0.0256

Ending population:
- Using the same calculations, p = 400/1000 = 0.4, q = 200/1000 = 0.2

Calculating genotype frequencies:
- BB (black fur): p^2 = 0.4^2 = 0.16
- BW (gray fur): 2pq = 2*0.4*0.2 = 0.16
- WW (white fur): q^2 = 0.2^2 = 0.04

Part B:

According to the Hardy-Weinberg equilibrium, the allele frequencies in a population will remain constant from generation to generation if certain conditions are met, including the absence of evolutionary forces such as mutation, gene flow, genetic drift, and natural selection.

In this case, the allele frequencies have changed from the beginning to the ending population, indicating that the population is evolving. This could be due to factors such as natural selection favoring certain fur colors, genetic drift, or migration of mice with different fur colors into the population.

One hypothesis to explain the changes in fur color frequencies could be that predators in the environment have a preference for mice with certain fur colors, leading to natural selection favoring those colors. For example, if black fur provides better camouflage in the environment, mice with black fur may have higher reproductive success, leading to an increase in the frequency of the black fur allele over time.