A spinner is divided into three equal parts A, B, and C. The repeated experiment of spinning the spinner twice is simulated 125 times. A table of outcomes is shown.
Outcome Frequency
A, A 15
A, B 12
A, C 10
B, A 18
B, B 15
B, C 17
C, A 11
C, B 13
C, C 14
Based on the table, for what probability can you expect the spinner to not land on B?
0.10
0.33
0.40
0.66
To find the probability that the spinner does not land on B, we need to calculate the combined frequencies of outcomes that do not include B.
From the table:
- Outcomes where B is not selected: A, A (15) + A, C (10) + C, A (11) + C, C (14) = 50
The total number of times the spinner was spun twice is 125.
Therefore, the probability that the spinner does not land on B is 50/125 = 0.40.
So, the correct answer is 0.40.