If 250 gN, and 18.75 g H, are used for this reaction, which reactant will be the limiting reactant?
To determine the limiting reactant, we need to compare the moles of each reactant to see which one will be completely consumed first.
First, we need to convert the masses of each reactant to moles using their molar masses:
1. Nitrogen (N₂): 28.02 g/mol
2. Hydrogen (H₂): 2.02 g/mol
250 g of nitrogen (N₂) is equivalent to 250 / 28.02 = 8.92 moles of N₂.
18.75 g of hydrogen (H₂) is equivalent to 18.75 / 2.02 = 9.29 moles of H₂.
Since 8.92 moles of N₂ is less than 9.29 moles of H₂, nitrogen (N₂) will be the limiting reactant in this reaction.