A ball is thrown into the air with an initial upward velocity of 60 ft/s. Its height (h) in feet after t seconds is given by the function h = –16t² + 60t + 6. What will the height be at t = 3 seconds?
(1 point)
Responses
35 feet
40 feet
42 feet
45 feet
To find the height at t = 3 seconds, plug in t = 3 into the function h = –16t² + 60t + 6:
h = -16(3)² + 60(3) + 6
h = -16(9) + 180 + 6
h = -144 + 180 + 6
h = 36 + 6
h = 42 feet
Therefore, the height at t = 3 seconds will be 42 feet. The answer is 42 feet.