A 5 kg stainless steel skillet is put on a stove top. How much heat will it take to change the temperature from 18°C to 70°C?
The specific heat of stainless steal is 452 * J/(k * g deg * C) (1 point)
117.5 kJ
O 12 kJ
O 23.5 kJ
125 kJ
To calculate the heat required, we can use the formula:
Q = mcΔT
Where:
Q = heat
m = mass of the skillet (5 kg)
c = specific heat of stainless steel (452 J/(kg * deg * C))
ΔT = change in temperature (70°C - 18°C = 52°C)
Plugging in the values:
Q = 5 kg * 452 J/(kg * deg * C) * 52°C
Q = 117,800 J = 117.8 kJ
Therefore, it will take 117.8 kJ of heat to change the temperature of the stainless steel skillet from 18°C to 70°C.
So the closest option is 117.5 kJ.