The area of a rectangle is 8x2+22x+15
. What are the possible dimensions of the rectangle? Use factoring.(1 point)
Responses
a. Length 4x+5 and width 2x+3
b. Length 4x+3 and width 2x+5
c. Length 4x−3 and width 2x−5
d. Length 4x−3 and width 2x+5
To find the dimensions of the rectangle, we need to factor the given expression for the area of the rectangle: 8x^2 + 22x + 15.
The factors of 8x^2 + 22x + 15 are (4x + 3)(2x + 5).
Therefore, the possible dimensions of the rectangle are length = 4x + 3 and width = 2x + 5.
So, the correct answer is:
b. Length 4x+3 and width 2x+5