Consider the graph that represents the following quadratic equation.
y=-1/3(x+2)^2+5
How does the graph open? Show your work.
The given quadratic equation is in vertex form, which is y = a(x-h)^2 + k. In this equation, (h,k) represents the vertex of the parabola.
In the given equation, a = -1/3, h = -2 and k = 5. Thus, the vertex of the parabola is at (-2,5).
Since a is negative in this case, the graph will open downwards.
Therefore, the graph of the given quadratic equation opens downwards.