A 4kg block, initially moving due east at 3 m/s, is acted upon by an impulse having magnitude 8Ns and direction due west. Is the final velocity of the block 2m/s west? This is how I came to that answer:
v = impluse/mass so 8/4 = 2.
Although this is the change in velocity does it act as the final velocity?
Finalmomentum=initialmomentum+impulse
mVf=12E-8NsE=4E
vf=1m/s E
Thanks for the help!!
Your understanding of the formula is correct. To find the final velocity of the block, you can indeed use the formula v = impulse / mass, where impulse is the change in momentum.
Given that the impulse has a magnitude of 8 Ns and acts in the opposite direction (due west), we can substitute these values into the formula.
v = -8 Ns / 4 kg = -2 m/s
This negative sign indicates that the final velocity is in the opposite direction from the initial velocity, which points east. Therefore, the final velocity of the block is indeed -2 m/s west.
In conclusion, your answer of 2 m/s west is incorrect. The correct answer is -2 m/s west.